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Thank you for the responses! So, assuming the neutral is to the right (20A), is the total load 40+40+20=100 or would i include the 20A the Neutral is carrying? OR is there some other calculation? I knew it would be a lot easier just asking here! Thanks.

Hi, I've spent hours trawling the internet to find the answer to what I thought was a pretty basic question but have failed thus far. So, I thought a trip to the "Horses Mouth" would yield a decent response. I am NOT an electrician, only having covered basic principles in my Engineering degree...