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Do-It-Yourself (DIY) Question & Answer Forum
A Thought Experiment
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<blockquote data-quote="Sidewinder" data-source="post: 350345" data-attributes="member: 9512"><p>No Specs,</p><p></p><p>The current divides FIRST, then the voltage divides.</p><p></p><p>You have too many unknown values to make a definitive calculation.</p><p></p><p>You have a current flowing proportional to a single winding, say R, and a current flowing proportional to two single windings, say 2R.</p><p></p><p>Now you have NO idea what R is, and in your example you have no idea what the current is, so how do you know what proportion of the current divides down each leg to state that it is the equations you give?</p><p></p><p>OK, just re-read your post, you cannot use numbers to prove your theory, you have to prove it with algebra else it is not a proof.</p><p></p><p>Sorry.</p><p></p><p>Plus you have based your theory on a voltage source, this is flawed, it must IMHO be a constant current source.</p></blockquote><p></p>
[QUOTE="Sidewinder, post: 350345, member: 9512"] No Specs, The current divides FIRST, then the voltage divides. You have too many unknown values to make a definitive calculation. You have a current flowing proportional to a single winding, say R, and a current flowing proportional to two single windings, say 2R. Now you have NO idea what R is, and in your example you have no idea what the current is, so how do you know what proportion of the current divides down each leg to state that it is the equations you give? OK, just re-read your post, you cannot use numbers to prove your theory, you have to prove it with algebra else it is not a proof. Sorry. Plus you have based your theory on a voltage source, this is flawed, it must IMHO be a constant current source. [/QUOTE]
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A Thought Experiment
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