Thanks for that, havent got round to doing it until now so here is my answer! Hope it is right!
Question A
IB = 8500/230 = 36.95A
IN = 45A (BS3036)
IT = Ca = N/A
Cg = 0.75
Cc= 0.725
Ci = N/A
45A / (0.75x0.725) = 82.75A
So far its 16mm @ 85A in table 4 something
Volt Drop = m/v/a x IB x L
1000
2.8 x 36.95 x 50
1000 = 5.17 v Which is within 5% of 230v
Is this right?
Thanks!