efficiency

[cm304eex]

HI all

This is my first post so be gentle with me

What is the correct formula for this question?

An electric machine has a power output of 1500 watts. The input current is 4A and the applied voltage is 400V. The efficiency of the machine will be:

Any help would be great.

 

[matt.leung]

output / input x 100

so:

output = 1500

input = 4 x 400 = 1600

1500/1600 = 0.9375

0.9375 x 100 = 93.75%

 

[sarni31]

Hi

Efficiency = Output / Input x 100(for percent)

so

the Output is 1500W

we need to calculate the input from 400v - 4A as Power

so

Power = Volts x Amps

400V x 4A = 1600W

so

1500W / 1600W = 0.93

expressed as percent

0.93 x 100 = 93% efficient

Guiness Drink

 

[Apache]

Hi Efficiency = Output / Input x 100(for percent)

so

the Output is 1500W

we need to calculate the input from 400v - 4A as Power

so

Power = Volts x Amps

400V x 4A = 1600W

so

1500W / 1600W = 0.93

expressed as percent

0.93 x 100 = 93% efficient

Guiness Drink

Not to be picky but 93.75 rounds up to 94% if you are not showing your decimal places

Welcome to the OP - we are gentle with everybody

 

[sarni31]

Not to be picky but 93.75 rounds up to 94% if you are not showing your decimal places Welcome to the OP - we are gentle with everybody

I stand corrected :coat

Thanks for that, though in my defense it is quite early

 

[cm304eex]

Ok I get it many thank's to you all!!

 

[a1]

11th, 12th & 13th Formula down on here: http://www.electricianforum.co.uk/electricalformulas.html

Welcome to the forum.