Help with Transposition of Formula..

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The easy way for Ohms Law is the TRIANGLE

V at the top and IR at the bottom

i= v_s/R (1-e^((-Rt) ⁄ L)

not sure what v_s is !
i / (v_s/R) = 1-e^((-Rt)/L) 


1-(i / (v_s/R)) = e^((-Rt)/L)
LN (1-(i / (v_s/R))) = (-Rt)/L
(LN (1-(i / (v_s/R))))/(-Rt) = L
 

Pi= ((360/y)x(H Sin y))/ (2xH) 

were y is the angle and H is the Hypotenuse 

 
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