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<blockquote data-quote="SPECIAL LOCATION" data-source="post: 79708" data-attributes="member: 250"><p>Bar 1.5 pivoted at the centre so there is 0.75m either side of pivot...</p><p></p><p>90M is applied 0.2m from one end...</p><p></p><p>e.g. (0.75-0.2) = 0.55 from the pivot...</p><p></p><p>Remember equal force equal length = Balance</p><p></p><p>Half the force but double the length on one side will also balance</p><p></p><p>Force &amp; length are proportional to each other either side of pivot!</p><p></p><p>So 90N is 0.55 from pivot..</p><p></p><p>How much force is needed 0.75 on other side of pivot?</p><p></p><p>90N x 0.55m MUST equal (x?)N x 0.75m</p><p></p><p>so</p><p></p><p>90x.55= 49.5</p><p></p><p>49.5 = (x?)N x 0.75m</p><p></p><p>49.5/0.75 = 66N</p><p></p><p>so 66N at one end will balance 90N 0.2m from other end!</p><p></p><p> <img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" class="smilie smilie--sprite smilie--sprite8" alt=":D" title="Big grin :D" loading="lazy" data-shortname=":D" /> </p><p></p><p>is that OK?</p><p></p><p>its nearly 1.00 am &amp; I have had a few Guiness DrinkGuiness DrinkGuiness Drink</p><p></p><p>ROTFWLROTFWLROTFWL</p></blockquote><p></p>
[QUOTE="SPECIAL LOCATION, post: 79708, member: 250"] Bar 1.5 pivoted at the centre so there is 0.75m either side of pivot... 90M is applied 0.2m from one end... e.g. (0.75-0.2) = 0.55 from the pivot... Remember equal force equal length = Balance Half the force but double the length on one side will also balance Force & length are proportional to each other either side of pivot! So 90N is 0.55 from pivot.. How much force is needed 0.75 on other side of pivot? 90N x 0.55m MUST equal (x?)N x 0.75m so 90x.55= 49.5 49.5 = (x?)N x 0.75m 49.5/0.75 = 66N so 66N at one end will balance 90N 0.2m from other end! :D is that OK? its nearly 1.00 am & I have had a few Guiness DrinkGuiness DrinkGuiness Drink ROTFWLROTFWLROTFWL [/QUOTE]
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