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Do-It-Yourself (DIY) Question & Answer Forum
Lighting Circuit Blowing........
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<blockquote data-quote="SPECIAL LOCATION" data-source="post: 28494" data-attributes="member: 250"><p>Assuming you have a dead short..</p><p></p><p>the live wire connected at the CU could be considered as at neutral potential.</p><p></p><p>In a normally wired circuit..</p><p></p><p>a bulb is places directly between the live &amp; neutral! <img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" class="smilie smilie--sprite smilie--sprite2" alt=";)" title="Wink ;)" loading="lazy" data-shortname=";)" /> </p><p></p><p>otherwise.. it don't work! <img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" class="smilie smilie--sprite smilie--sprite1" alt=":)" title="Smile :)" loading="lazy" data-shortname=":)" /> <img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" class="smilie smilie--sprite smilie--sprite2" alt=";)" title="Wink ;)" loading="lazy" data-shortname=";)" /> </p><p></p><p>The only difference is..</p><p></p><p>normally the bulb is protected by a 5A or 6A fuse / MCB</p><p></p><p>bypassing the CU fuse is now a circuit without any protection other than the property incoming fuse!</p><p></p><p>Personally its a method I wouldn't recommend</p><p></p><p>strictly speaking there is a bit of flex going to your lamp holder without proper overload protection. <img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" class="smilie smilie--sprite smilie--sprite9" alt=":eek:" title="Eek! :eek:" loading="lazy" data-shortname=":eek:" /> </p><p></p><p>spose you could wire it via a plug with 3A or 5A fuse? to make it a bit safer? <img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" class="smilie smilie--sprite smilie--sprite2" alt=";)" title="Wink ;)" loading="lazy" data-shortname=";)" /> <img src="data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7" class="smilie smilie--sprite smilie--sprite1" alt=":)" title="Smile :)" loading="lazy" data-shortname=":)" /></p></blockquote><p></p>
[QUOTE="SPECIAL LOCATION, post: 28494, member: 250"] Assuming you have a dead short.. the live wire connected at the CU could be considered as at neutral potential. In a normally wired circuit.. a bulb is places directly between the live & neutral! ;) otherwise.. it don't work! :) ;) The only difference is.. normally the bulb is protected by a 5A or 6A fuse / MCB bypassing the CU fuse is now a circuit without any protection other than the property incoming fuse! Personally its a method I wouldn't recommend strictly speaking there is a bit of flex going to your lamp holder without proper overload protection. :o spose you could wire it via a plug with 3A or 5A fuse? to make it a bit safer? ;) :) [/QUOTE]
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