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Student & Learning Zone - City & Guilds
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<blockquote data-quote="NozSpark" data-source="post: 113109" data-attributes="member: 601"><p>I think one of your numbers is still wrong....</p><p></p><p>I can't work it out.</p><p></p><p>If you work it backwards with the figures they give..</p><p></p><p>Parallel resistance = (20*2.86)/(20+2.86) = 2.5 ohms</p><p></p><p>+ the series resistor (5ohms) =7.5ohms</p><p></p><p>Now if you take the voltage and divide by resistance you get</p><p></p><p>30/7.5 = 4A</p><p></p><p>which is not what the question gives</p><p></p><p>Now if the series resistor was 50ohms then that would be alot closer!!</p></blockquote><p></p>
[QUOTE="NozSpark, post: 113109, member: 601"] I think one of your numbers is still wrong.... I can't work it out. If you work it backwards with the figures they give.. Parallel resistance = (20*2.86)/(20+2.86) = 2.5 ohms + the series resistor (5ohms) =7.5ohms Now if you take the voltage and divide by resistance you get 30/7.5 = 4A which is not what the question gives Now if the series resistor was 50ohms then that would be alot closer!! [/QUOTE]
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