resistors again

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NWDS

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Evening fellas can any of you kind hearted gentlemen help with the question below ??,

A cable carries a current of 65A with a 13v drop. what must be the resistance of a cable wich,when connected in parrallel with the first cable, will reduce the voltage drop to 5v.

As before fellas if you have the answer and the means I would be grateful.

regards Iain

 

The Godfather

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5V / 65A = 0.076923 ohms, which is the required resistance to achieve (from both cables in parallel).

We have 13V / 65A = 0.2 ohms

So at 5V across 0.2 ohms = 25A

Then the new cable will be 5V / 40A = 0.125 ohms

0.2 x 0.125 / 0.2+0.125 = 0.076923 ohms

The Godfather

 

NWDS

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Thank you God Father, may your first grand child be a masculine one.

 
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