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Student & Learning Zone - City & Guilds
resistors in parallel
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<blockquote data-quote="SPECIAL LOCATION" data-source="post: 13936" data-attributes="member: 250"><p>The other way you can check Parallel resistors is use the "Product" over "Sum" method.</p><p></p><p>e.g.</p><p></p><p>two resistors R1 &amp; R2 in parallel.</p><p></p><p>res = (R1 x R2)/(R1 + R2).</p><p></p><p>with 3 resistors you can calc two of them first then Calc third afterwards..</p><p></p><p>i.e.</p><p></p><p>4 &amp; 6 in parallel is (4x6)/(4+6) = 24/10 = 2.4</p><p></p><p>now do</p><p></p><p>2.4 &amp; 9 in parallel is (2.4x9)/(2.4+9) = 21.6/11.4 = 1.89473 etc.. =<strong>1.89 </strong></p><p></p><p>which proves you have your calc correct using the other 1/R1 + 1/R2 + 1/R3 = 1/Rx method.</p></blockquote><p></p>
[QUOTE="SPECIAL LOCATION, post: 13936, member: 250"] The other way you can check Parallel resistors is use the "Product" over "Sum" method. e.g. two resistors R1 & R2 in parallel. res = (R1 x R2)/(R1 + R2). with 3 resistors you can calc two of them first then Calc third afterwards.. i.e. 4 & 6 in parallel is (4x6)/(4+6) = 24/10 = 2.4 now do 2.4 & 9 in parallel is (2.4x9)/(2.4+9) = 21.6/11.4 = 1.89473 etc.. =[B]1.89 [/B] which proves you have your calc correct using the other 1/R1 + 1/R2 + 1/R3 = 1/Rx method. [/QUOTE]
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resistors in parallel
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