Hey all I've just started my last exam for the 203 & have started covering different formula on Impedance, Capacitive, Inductive etc. But when it came to putting the formulas in practice am stuck on one small part of this formula. "I took this formula from the text book I got to work out."
Calculate the Reactance of a 150uF capacitor and a 0.05 H inductor if they were separately connect to the 50Hz mains supply
Capacitive Reactance
f = 50hz & C = 150uF 150 x 10-6 F
I keep getting 20.9 on my calculator for the Cap Reactance "stuck on the 150 x 10-6" it is 150 / 1.000.000 right?
Inductive Reactance "easy one"
F = 50 Hz & L = 0.05
Am probly missing something so simple but I've gone mad not working this out lol
Calculate the Reactance of a 150uF capacitor and a 0.05 H inductor if they were separately connect to the 50Hz mains supply
Capacitive Reactance
Xc = 1/2piFC
f = 50hz & C = 150uF 150 x 10-6 F
1/(2 x PI x 50 x 150uF x 10-6 = 21.2ohms
I keep getting 20.9 on my calculator for the Cap Reactance "stuck on the 150 x 10-6" it is 150 / 1.000.000 right?
Inductive Reactance "easy one"
XL = 2PIfl
F = 50 Hz & L = 0.05
XL = 2 x PI x 50Hz x 0.05 H = 15.7ohms "that I can work out"
Am probly missing something so simple but I've gone mad not working this out lol