got a couple of questions

[NWDS]

Q1, A cable carries a current of 65 A with a volt drop of 13v. What must the resistance of a cable wich, when connected in parallel with the first cable, will reduce the volt drop to 5V.

Q2, To vary the speed of a D.C. series motor it is usual to connect a diverter resistor in parallel with the field winding. The field of a series motor has a resistance of 0.6 ohms and the diverter resistor has three steps,of 5ohm,4ohm and 2ohm. Assuming that the total current is fixed at 28A, find out how much current flows through the field windings at each step of the resistor.

Iam trying these and not getting any were.

thanks in advance fellas and ladies

NWDS

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[L-E_Fault]

pass, next question

 

[The Godfather]

Question 1

13V/65A = 0.2ohm

5V/65A = 0.0769ohm

0.2ohm-0.079ohm = 0.1231ohm

The Godfather

 

[NWDS]

Thanks Godfather, I had got up to working out the two resistances, I could not work out how to get the answer, I was using ohms law but getting no were, I did not think of subtracting.

Thanks Don.

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