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resistors again
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<blockquote data-quote="The Godfather" data-source="post: 14458" data-attributes="member: 218"><p>5V / 65A = 0.076923 ohms, which is the required resistance to achieve (from both cables in parallel).</p><p></p><p>We have 13V / 65A = 0.2 ohms</p><p></p><p>So at 5V across 0.2 ohms = 25A</p><p></p><p><strong>Then the new cable will be 5V / 40A = 0.125 ohms </strong></p><p></p><p>0.2 x 0.125 / 0.2+0.125 = 0.076923 ohms</p><p></p><p>The Godfather</p></blockquote><p></p>
[QUOTE="The Godfather, post: 14458, member: 218"] 5V / 65A = 0.076923 ohms, which is the required resistance to achieve (from both cables in parallel). We have 13V / 65A = 0.2 ohms So at 5V across 0.2 ohms = 25A [B]Then the new cable will be 5V / 40A = 0.125 ohms [/B] 0.2 x 0.125 / 0.2+0.125 = 0.076923 ohms The Godfather [/QUOTE]
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