Hi all, I am only a newbie and do not pretend to know it all, and I am rather worried that i might have a bit of a problem here, and so some advice is needed!!
Firstly; I have a 70 odd year old house with a single phase supply [TNS] House is on Line 2. Ze is .27 with PEFC 863A [Line to neutral is almost the same with supply impedance .28 and PSSC 827A
Secondly; I have a shed behind the house with a 3 phase PME supply. This supply is connected to the main only about 5 feet away from the house supply. This supply was installed only about 9 months ago.
I did some testing on shed today, here are the results;
Ze;
L1 = .30
L2 = .79
L3 = .32
Line to neutral currents are;
L1 = 810A
L2 = 313A
L3 = 853A
Phase to phase currents are;
L1 - L3 = 1.91KA
L1 - L2 = 458A
L2 - L3 = 469A
I can only think that the much lower currents [both to earth and neutral] can only mean that there is a faulty joint in L2 where the service cable joins the main??
If L2 to neutral in the house has an impedance of .28 and L2 to neutral in the shed has an impedance of about .76 then that is a difference of .48 of an ohm. So for a current of 80A down that phase, there would be a volt drop of 38.4 volts. Volts squared divided by resistance gives power. So this gives 3000 odd watts.
Something is going to get very hot, very quickly...
Am i right in all this, and what should i do??
john...
Firstly; I have a 70 odd year old house with a single phase supply [TNS] House is on Line 2. Ze is .27 with PEFC 863A [Line to neutral is almost the same with supply impedance .28 and PSSC 827A
Secondly; I have a shed behind the house with a 3 phase PME supply. This supply is connected to the main only about 5 feet away from the house supply. This supply was installed only about 9 months ago.
I did some testing on shed today, here are the results;
Ze;
L1 = .30
L2 = .79
L3 = .32
Line to neutral currents are;
L1 = 810A
L2 = 313A
L3 = 853A
Phase to phase currents are;
L1 - L3 = 1.91KA
L1 - L2 = 458A
L2 - L3 = 469A
I can only think that the much lower currents [both to earth and neutral] can only mean that there is a faulty joint in L2 where the service cable joins the main??
If L2 to neutral in the house has an impedance of .28 and L2 to neutral in the shed has an impedance of about .76 then that is a difference of .48 of an ohm. So for a current of 80A down that phase, there would be a volt drop of 38.4 volts. Volts squared divided by resistance gives power. So this gives 3000 odd watts.
Something is going to get very hot, very quickly...
Am i right in all this, and what should i do??
john...