Hi
I have 5 questions with answers with are:
1) A resistor of 28_ is connected to a inductor of 12mH and a capacitor of 24μF. Calculate
the impedance presented to the 50Hz supply.
XL = 2πfL = 3.77_, XC = 1 / (2πfC) = 132.63_, Z = √ (R2 + (XC- XL)2 = 131.87_
2) A resistor of 38_ is connected to a inductor of 124mH and a capacitor of 100μF.
Calculate the impedance presented to the 50Hz supply.
XL = 2πfL = 38.96_, XC = 1 / (2πfC) = 31.83_, Z = √ (R2 + (XL- XC)2 = 38.66_
3) A resistor of 12k_ is connected to a inductor of 56.92mH and a capacitor of 178μF.
Calculate the impedance presented to the 50Hz supply.
XL = 2πfL = 17.88_, XC = 1 / (2πfC) = 17.88_, In this case XL=XC, so Z=R = 12k_
4) A resistor of 164_ is connected to a inductor of 84mH and a capacitor of 18μF. Calculate
the impedance presented to the 50Hz supply.
XL = 2πfL = 26.39_, XC = 1 / (2πfC) = 176.84_, Z = √ (R2 + (XC- XL)2 = 222.56_
5) A resistor of 216_ is connected to a inductor of 136mH and a capacitor of 124μF.
XL = 2πfL = 42.73_, XC = 1 / (2πfC) = 25.67_, Z = √ (R2 + (XL- XC)2 = 216.67_
Does anyone know how to work them out as im having problems getting the correct answer.
thanks
I have 5 questions with answers with are:
1) A resistor of 28_ is connected to a inductor of 12mH and a capacitor of 24μF. Calculate
the impedance presented to the 50Hz supply.
XL = 2πfL = 3.77_, XC = 1 / (2πfC) = 132.63_, Z = √ (R2 + (XC- XL)2 = 131.87_
2) A resistor of 38_ is connected to a inductor of 124mH and a capacitor of 100μF.
Calculate the impedance presented to the 50Hz supply.
XL = 2πfL = 38.96_, XC = 1 / (2πfC) = 31.83_, Z = √ (R2 + (XL- XC)2 = 38.66_
3) A resistor of 12k_ is connected to a inductor of 56.92mH and a capacitor of 178μF.
Calculate the impedance presented to the 50Hz supply.
XL = 2πfL = 17.88_, XC = 1 / (2πfC) = 17.88_, In this case XL=XC, so Z=R = 12k_
4) A resistor of 164_ is connected to a inductor of 84mH and a capacitor of 18μF. Calculate
the impedance presented to the 50Hz supply.
XL = 2πfL = 26.39_, XC = 1 / (2πfC) = 176.84_, Z = √ (R2 + (XC- XL)2 = 222.56_
5) A resistor of 216_ is connected to a inductor of 136mH and a capacitor of 124μF.
XL = 2πfL = 42.73_, XC = 1 / (2πfC) = 25.67_, Z = √ (R2 + (XL- XC)2 = 216.67_
Does anyone know how to work them out as im having problems getting the correct answer.
thanks