It would be; Line voltage [400v] x the current [in one phase] x square root of three [1.732]
All this assumes a "balanced load" I.E. all three phases are carrying the same current.
OR
Phase voltage [230v] x current [in one phase] x 3
If you did it this way, i am not sure of the effect of an unbalanced load, although i am sure other forum members will be able to assist you with this [bit beyond me!]
Anyway, the answer would be in KW.
If you wanted KVA you would have to multiply the result by [PF x Efficiency]
I think what you mean is, that as i was referring to quantities measured in "thousands" [of watts] the correct prefix would [should] have been a lower case "k" [to denote "kilo" as in 1000] and not an upper case "K" that denotes a different quantity!! [1024]
Sort of [but not quite] along the same lines as mW are most very certainly not the same as MW!!!!!!
I have to say, i think this forum is brilliant!! Best one by far!!