Ohms law

[L Plate]

could anyone show me pls how to work this out ...

What is the TOTAL POWER in the circuit shown here if R1 =6 ohms and R2 = 7 ohms and R3 = 8 ohms and R4 = 9 ohms and R5 = 10 ohms and SUPPLY VOLTAGE is 50v?

thank you

 

[NozSpark]

Is this a series or parallel circuit???

Series

10+9+8+7+6=40ohms

I=V/R

I=50/40

I=1.25A

P=I*V

P=1.25*50

P=62.5watts

Parallel

1/R=1/R1+1/R2+1/R3+1/R4+1/R5

1/R=1/6+1/7+1/8+1/9+1/10

1/R=0.645

R=1.54

I=V/R

I=32.46A

P=I*V

P=32.46*50

P=1623watts

 

[L Plate]

Is this a series or parallel circuit???Series

10+9+8+7+6=40ohms

I=V/R

I=50/40

I=1.25A

P=I*V

P=1.25*50

P=62.5watts

Parallel

1/R=1/R1+1/R2+1/R3+1/R4+1/R5

1/R=1/6+1/7+1/8+1/9+1/10

1/R=0.645

R=1.54

I=V/R

I=32.46A

P=I*V

P=32.46*50

P=1623watts

Hello Sir,

My head is really in trouble about this,,, the way how you explain your calculation is pretty understandlbe and looks easy to work out , but this practice materials i'm using is bit different...

the answer for that question is

156.5.watts ....

and this is what it says

"remember work the parallel circuit out first then add it to the series connected resistor. Then use ohms LAW to find P, once I total is known"

 

[Apache]

Hello Sir,My head is really in trouble about this,,, the way how you explain your calculation is pretty understandlbe and looks easy to work out , but this practice materials i'm using is bit different...

the answer for that question is

156.5.watts ....

and this is what it says

"remember work the parallel circuit out first then add it to the series connected resistor. Then use ohms LAW to find P, once I total is known"

Sounds like you have a mix of series and parallel. Have you got a circuit diagram?

 

[L Plate]

Sounds like you have a mix of series and parallel. Have you got a circuit diagram?

yea it the diagram it says

R1 and R2 in parallel

R3 connected from r1/r2 in series

R4 and R5 connected from r3 in parallel

 

[Riggy]

yea it the diagram it saysR1 and R2 in parallel

R3 connected from r1/r2 in series

R4 and R5 connected from r3 in parallel

OK, now we have all the info, the early shift can have a go:

R1 + R2 in parallel = 1/((1/6)+(1/7)) = 3.231ohm

R4 + R5 in parallel = 1/((1/9)+(1/10) = 4.737ohm

Total R therefore = 3.231ohm + 8ohm + 4.737ohm = 15.968ohm

I = V/R = 50V/15.968ohm = 3.131A

P = V x I = 50V x 3.131A = 156.55W

 

[L Plate]

OK, now we have all the info, the early shift can have a go:R1 + R2 in parallel = 1/((1/6)+(1/7)) = 3.231ohm

R4 + R5 in parallel = 1/((1/9)+(1/10) = 4.737ohm

Total R therefore = 3.231ohm + 8ohm + 4.737ohm = 15.968ohm

I = V/R = 50V/15.968ohm = 3.131A

P = V x I = 50V x 3.131A = 156.55W

thank you , i got it ... thanks to all who shared thier ideas

have a nice day all

 

[Andy™]

yea it the diagram it saysR1 and R2 in parallel

R3 connected from r1/r2 in series

R4 and R5 connected from r3 in parallel

often useful to give all the info in the first post...