power factor

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PoorFish

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what is the power factor of a circuit with a 4 ohms resistor and a 10mH inductor??

any ideas anyone

I have tried the R/Z formula but it doesnt seem to work

regards P

 
Hey I posted the exact same question as you a few days ago with the same title :p here is your awnser credits go to wayne

Find Z first

Z = √R
 
cheers Bobby

getting late and been at this too long tonight

i must have looked at that post a number of times already

thanks for reply will look at it closer tomorrow

PatGuiness Drink

 
for this question do you not have to work out the xl inductive reactance? -

(xl = 2 x crbvcurbvubruvbruvb x f x l) xl = 2x3.14x50x(10x10-3=0.01) to work out impedance?

I get

R = 4ohms

Z = 4ohms

so pf = R/Z = 4/4 = 1

is that correct?

 
for this question do you not have to work out the xl inductive reactance? - 2x3.14x50x(10x10-3=0.01) to work out impedance?

I get Z = 4ohms so pf = R/Z = 4/4 = 1
????

 
I would agree you need to work out the imductive reactance XL.

With no frequency given you can only assume 5o Hz so

XL = 2 x 3.14 x 50 x (10 x 10-3)

XL = 3.14 ohms

Impeadance (Z) is the Square Root of (R squared + XL squared)

Z = Root ((4 x 4) + (3.14 x 3.14))

Z = 5.08

pf = R / Z

pf = 0.78

All on the assumption of 50Hz supply!!!!!!!

 
maybe im missing something butXL = 2 x 3.14 x 50 x (10 x 10-3)

XL = 3.14 ohms

is 31.4 ohms
Don't put in the 10 in the 10-3, that might be where you're going wrong.

10 x 10-3 = 0.01 10 to the power minus 3 (or 10 / 1000)

so try 2 x 3.14 x 50 x 0.01

that comes out as 3.14 ohms

 
DSCF1549.jpg
(i know its a bad pic, had to cover the flash or it just blinded everything)
I prefer a Caseo over the Sharpe - especially if it can't calculate properly............

 
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