P=Vcan any one show me how to go on with this ?if a purley inductive load having an inductive reactance of 10 is connected across a 100v 50Hz supply,the power dissipated in the circuit will be ?
thanks.
andy.c can you explain where the V
I thought this as well but the fact the he says "inductive reactance of 10" suggested that it has resistance (XL=2*Pi*F*L). ...,Guys,I think we may have missed the point here..... The question says a PURELY inductive load. In which case it has no resistive component only an inductive one, hence the POWER dissipated is zero Watts.
Adrian
I thought this as well but the fact the he says "inductive reactance of 10" suggested that it has resistance (XL=2*Pi*F*L). ...,Shouldn
Hello Adrian...... you may well be right....Guys,I think we may have missed the point here..... the question says a PURELY inductive load. In which case it has no resistive component only an inductive one, hence the POWER disipated is zero Watts.
I agree that it will consume reactive power, in VAr, and hence have an apparent power, in VA, but it cant consume any WATTS.
Adrian
Is the earth flat?on to me level 3 now do city & guilds make the questions more clearer as the corses go on ?
Oh they do enjoy tripping people up! :|The question has been worded pity much as City and Guilds ask them. I'm sure they mean to confuse people.The answer they are looking for is 0 watts. I'm not too sure why, is it because it's purely inductive so has a power factor of 0? Hence 0 x anything = 0.I've learnt to spot the question by the 'purely' in it.
I have got to say I think your twopenny worth is actually more like a sixpence!If we assume, for the moment, that the question is poorly worded and assume that we have been given the impedance of the inductor and not the inductance. However, we still have a problem...... if we calaculate the current flowing through this inductor and muliply by the applied voltage we will get the apparent power which is measured in VA (not WATTS)The problem here is that not all the apparent power is dissipated..... only real power can be dissipated. The Reactive power component merely flows backwards and forwards between the source and the load each half cycle.
We don't have enough information available to split the apparent power into its component parts of real & reactive powers.
Just my twopenny worth.......
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