transformers

[NWDS]

Afternoon everyone, can some one check this ??? please

A transformer is rated @10kW but is only delivering 9.8kW, copper losses are 0.33kW & iron losses are 0.2kW, calculate the efficiency of the transformer.

Answer given is 90.4%

output/input ( + losses ) = 90.4%

9.8/10.83*100 = 90.4%

Losses are 0.33 kW + 0.2 kW = 0.53 add to the input gives 10.53

9.8/10.53*100 = 93.06 %

How did they get 10.83 ?????????.

 

[NWDS]

Just read another post the same as mine, Iam off to see if i can work it out now.

NWDS

 

[NWDS]

Now Iam still stuck, one of searleys post has the same question I have checked how it has been answered and still cannt get it ( the figure quoted ).

Machinery efficiency is output/input*100 =

transformer efficiency is output/output + losses

9.8/9.8+0.2+0.33*100 = 94%

the original answer was given as 90.4% ??? any ideas.

 

[msb2003]

My guess someone mistyped a bit! your right with the output/output+losses x 100 for a transformer.

 

[NWDS]

Thanks msb, I have been using the swindon-massive site but have a few concerns now.

NWDS

 

[msb2003]

Thanks msb, I have been using the swindon-massive site but have a few concerns now.NWDS

I refer people to there but it does have some errors!!