R1 + R2 for the cable is 0.2488
Ze for the supply is..
TNS 0.8
TNCS 0.35
This will give a Zs of..
TNS 1.0488
TNCS 0.5988
And that mind you, is BEFORE you allow for the increase in R1 + R2 under fault conditions due to cable heating...
Well like i said, there are a few snags here.
Zs is going to be 1.0488 for TNS and 0.5988 for TNCS and, having allowed for cable heating under fault conditions, for a 63A "B" curve you want a max Zs of 0.583 and for a "C" curve, 0.292..
There is no doubt about it, a 63A WILL take you over the required Zs so an RCD will have to be used to achieve disconnection times required in the event of an earth fault. What about L/L or L/N faults though?? Disconnection times for these could well be longer than 5 seconds..
Ok, so there is no requirement as to disconnection times whatsoever [APART from in the event of an earth fault] but the amount of heat a cable can withstand in the event of a fault, is, as far as i know, based on 5 second disconnection times.
If you go over this, then you are on your own!! The values for "K" in the adiabatic equation are all based on 5 seconds so far as i know, but does this just apply to a CPC?? Not sure, i am only a welder you see, and it is a long time since i fiddled about with any electrics..
john..