are most 80-100a CU rcd's. rcd's or rcbo's?

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Lee321

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all in the title i think.

hard to imagine that with the feel of a mcb in the way it turns on/off that they won't be rcbo's?

i ask as i have a rcd to en61008 that does trip with excessive load!

?

 
all in the title i think.hard to imagine that with the feel of a mcb in the way it turns on/off that they won't be rcbo's?

i ask as i have a rcd to en61008 that does trip with excessive load!

?
You mean RCCD? Are you sure its tripping due to current and not another reason like termal effects? They are rated in the same way a JB or light switch is in that it won't protect from over current but has only been designed to work up to that maximum current.

 
well a thermal effect would be operation for overcurrent wouldn't you say?

whats the diff between rccd , rcbo? none i thought

 
My point was more not by design but due to circumstance.

RCCD is a Residual Current Circuit Breaker

RCBO is an RCCD with over current protection.

 
so an rccd is a rcd?

i.e with no overload protection

i can't see it being

rccd= fault protection only or overload protection only

where

rcd= no fault or overload protection

rcbo= fault & overload protection

 
so an rccd is a rcd?i.e with no overload protection

i can't see it being

rccd= fault protection only or overload protection only

where

rcd= no fault or overload protection

rcbo= fault & overload protection
I think you are confusing yourself there. There is no device called an RCD. Its a "class" of devices that both an RCCD and RCBO (along with SRCD, PRCD and SRCB) are members of.

 
Hi,

I might be wrong, but this is how I see it:

If you have a 30mA RCD protecting, say, 5 circuits, and under normal operating conditions these circuits draw 20A.

If you have a combined earth leakage of 15mA, this wouldn't be a problem.

If the combined load then increased to 40A, then the amount of current flowing down the earth path would increase in proportion (30mA) and trip the RCD.

So, although there's no overload protection, it could still trip under excessive loads.

The only way to solve it would be to get rid of as much of the leakage as possible.

Or have I got this wrong? :D

 
OK.

The RCD variant known as an RCCD; which we commonly call "an RCD", will provide earth leakage protection, yet has NO capability for overcurrent protection. (I have seen one installed on a shower supply, henley`d straight off the tails, into a 2 module enclosure containing a 63A/30mA RCD. That circuit has NO overcurrent protection whatsoever.

The RCD variant known as an RCBo, which we commonly call "an RCBo", provides overcurrent protection, and earth leakage protection.

HTH

KME

 
Earth faults (L-E or N-E) have nothing to do with the load attached to the circuit..
Normal circuit theory says they must have.

Current in a series circuit remains constant throughout.

If you introduce a N - E fault, you are introducing a parallel path back.

Current in a parallel circuit will split down each leg of the parallel path in proportion to the resistance of each leg.

If the resistance of the two paths remains the same, and you increase the current (the load), then it stands to reason that the current down each parallel return will increase.

So, circuit current - 10 A.........N - E leakage 15 mA

circuit current - 20 A.........N - E leakage 30mA

 
Normal circuit theory says they must have.Current in a series circuit remains constant throughout.

If you introduce a N - E fault, you are introducing a parallel path back.

Current in a parallel circuit will split down each leg of the parallel path in proportion to the resistance of each leg.

If the resistance of the two paths remains the same, and you increase the current (the load), then it stands to reason that the current down each parallel return will increase.

So, circuit current - 10 A.........N - E leakage 15 mA

circuit current - 20 A.........N - E leakage 30mA
thats wrong ads

the leak will only draw what ever current is drawn due to its resistance value

regardless of the load.

i.e a lighting circuit that has 10 lighting points but only 1 is switched on and the leakage is 10ma turn the other 9 on and the leakage will be the same as long as no other leaks are connected with the other 9

 
Sorry in this case it doesn't work like that..

The load that you are changing is in parallel with the fault.

If you had parallel resistances and then a series load then the current would change, but an earth fault uses different return path...

You need to draw it out then you will see..

 
thats wrong adsthe leak will only draw what ever current is drawn due to its resistance value

regardless of the load.
So how much leakage will there be, exactly, in a circuit with a N - E fault

with no load?? :D

Of course it's reliant on the load.

 
Where's this leakage come from? That has nothing to do with the overload characteristics of an RCD, of which there are none. If you have a leakage the RCD operates as it is doing it's job of protecting against leakage to earth. If there are no faults there is no leakage, ergo it doesn;t trip, and just melts.

 
So how much leakage will there be, exactly, in a circuit with a N - E fault
there has to be some load but how much is irrelevant

what is the value of the resistance of the fault?

 
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