Ok had a go at making a cable calculation up, had a go
A 230v 11KW shower single phase load is run through twin & Earth pvc 70 degrees operating temperature and has a distance of 15metres through joists in a loft extention. the ambient temperature is 30 degrees C and the circuit uses a semi enclosed fuse (BS3036)
Work out!
a) Design current
B) Installation method
c) protective device rating
d) Correction Factor
e) Minimum cable rating
f) Minimum cable size
g) Volt Drop
h) Volt Drop allowed
a: (Ib Design Current) 11000/230 = 47.82A
b: Reference Method C (clipped Direct)
c: (In Protective Device) = 50A BS 3036
d Correction factor from ambient Temperature
30 = 0.94
e: It = 50/0.94 x 0.725 = 73.36A
Ca = 1
Cg = 1
cc = 0.725 semi enclosed bs 3036
ci = 1
f: 16mm cable size is choosen from 87A Reference Method C
g: (mV/A/M)/1000
2.8 x 47.82 x 15 / 1000 = 2.00Volts drop
h: 5% other uses. 11.5volt drop maximum. Which means it's acceptable
If I've made a mistake would anyone be able to point me where I went wrong please.
Cheers
A 230v 11KW shower single phase load is run through twin & Earth pvc 70 degrees operating temperature and has a distance of 15metres through joists in a loft extention. the ambient temperature is 30 degrees C and the circuit uses a semi enclosed fuse (BS3036)
Work out!
a) Design current
B) Installation method
c) protective device rating
d) Correction Factor
e) Minimum cable rating
f) Minimum cable size
g) Volt Drop
h) Volt Drop allowed
a: (Ib Design Current) 11000/230 = 47.82A
b: Reference Method C (clipped Direct)
c: (In Protective Device) = 50A BS 3036
d Correction factor from ambient Temperature
30 = 0.94
e: It = 50/0.94 x 0.725 = 73.36A
Ca = 1
Cg = 1
cc = 0.725 semi enclosed bs 3036
ci = 1
f: 16mm cable size is choosen from 87A Reference Method C
g: (mV/A/M)/1000
2.8 x 47.82 x 15 / 1000 = 2.00Volts drop
h: 5% other uses. 11.5volt drop maximum. Which means it's acceptable
If I've made a mistake would anyone be able to point me where I went wrong please.
Cheers