How to work this out

[skystorm]

Hi all mind blank

The current in a coil changes from 5A and 2A in 0.05seconds and induces a voltage of 30v in the coil, the inductance of the coil is = 2x 0,05=

30v

,If a current consists of two resisters of 5ohms and 2ohms are connected in series,If a current of 5A flow in the circuit the power dissipated in the 2ohms risistor will be =

regards

 

[sparkytim]

We are not here to answer your home work for you.

Make some effort and you may get some assistence

 

[Manator]

What do you get when you try and work it out? Show us your workings if you are wrong we can show you where you went wrong, if you are right we can explain why you get that answer and give examples of how to work them out. Giving you the answer right out will not teach you how, and will not allow you to understand the process. When it clicks in your mind, you will be able to carry out these calculations without any difficulty.

So have a go and let us see if we can put you right.

 

[skystorm]

A I2xR = Watts(50watts

B 2x3,142x 50x2x0,05 = 1,5H

Like getting told off by a teacher .lol

only had a mind blank

 

[SPECIAL LOCATION]

Hi all mind blank The current in a coil changes from 5A and 2A in 0.05seconds and induces a voltage of 30v in the coil, the inductance of the coil is = 2x 0,05=

30v

,If a current consists of two resisters of 5ohms and 2ohms are connected in series,If a current of 5A flow in the circuit the power dissipated in the 2ohms risistor will be =

regards

Are there two questions here.....

Should "current" be circuit?

A I2xR = Watts(50wattsB 2x3,142x 50x2x0,05 = 1,5H

Like getting told off by a teacher .lol

only had a mind blank

and have you attempted them in reverse order here???

The current in a coil changes from 5A and 2A in 0.05seconds and induces a voltage of 30v in the coil, the inductance of the coil is

maybe........

have a read here...

Inductance - Wikipedia, the free encyclopedia

EMF = L(in henries) x (change in current / time)

have you got enough values to maybe try this formula????

,If a circuit consists of two resisters of 5ohms and 2ohms are connected in series,If a current of 5A flow in the circuit the power dissipated in the 2ohms risistor will be =

If

Power = IxV

and V = IxR

So Power =Ix(IxR)

or I2xR

put the numbers in and cruch... :|