Ohms law

[L Plate]

please can anyone show me the calculation on this one pls.

What is the CURRENT at A in the circuit shown here if R1 = 10k ohms and R2 = 63ohms and VOLTAGE SUPPLY is 50v ?

I am bit confused with the 10k ohms unit , I am alright solving it if it is all in ohms unit...a bit of help please.

BTW it's in parallel

thank you

answer is 0.8A

 

[Apache]

It's just the same!

10kohm = 10,000 ohms

so

1/R = 1/R1+1/R2

1/R = 1/10,000 + 1/63

1/R = 0.01597

R = 62.6ohm (see how negligable the 10,000 ohm resistor is )

V=IR or I=V/R

I = 50v/62.6ohm

I = 0.8A

see

it's just the same

1 kilo gram is 1,000 grammes

1 kilo watt is 1,000 watts

 

[L Plate]

It's just the same!10kohm = 10,000 ohms

so

1/R = 1/R1+1/R2

1/R = 1/10,000 + 1/63

1/R = 0.01597

R = 62.6ohm (see how negligable the 10,000 ohm resistor is )

V=IR or I=V/R

I = 50v/62.6ohm

I = 0.8A

see

it's just the same

1 kilo gram is 1,000 grammes

1 kilo watt is 1,000 watts

thank you very much , really helpful..have a nice day