what is the total power

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NWDS

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Evening all can I have some help please,

what is the total power in the circuit shown here if,

R1= 6 ohms ( 1/6 = 0.1666 )

R2= 7 ohms ( 1/7 = 0.1428 both in parallel )

R3= 8 ohms ( series )

R4= 9 ohms (1/9 = 0.1111 )

R5= 10 ohms (1/10 = 0.1 both in parallel )

the supply voltage is 50v,

I have got it as far as working out my parallel then adding them to my series, but have blanked out on the rest.

thanks in advance fellas.

NWDS

 
if R1 and R2 are in parallel

R4 and R5 and in parallel

and R8 is in series with those

then I would say that the total power is

156.25 watts or there about

 
Yes that is the answer, but how did you get to that figure ???.

NWDS

 
Bloody scanner

Right

1/(1/6 + 1/7) = 3.23 ohms ish

1/(1/9 + 1/10) = 4.7 ohms ish

8 ohms

add the three

15.9 about 16 ohms

Right

I = V / R

P = V * I

Substitute I

You get

P = V * V/R

which is V^2 (V squared) divided by R

so 50^2/ 16 = 156.2 Watts

Hope that helps

I Hate scanners!!

 
I had a crackin diagram, with stick figures, dancing girls and a whole stage full of kids singing. Sorry you will have to settle with my ascii crap!!

The Dancing girls looked brilliant, each one had a Resistor 6, 7, 8 9 and 10 ohms!!

Damn my scanner!!

 
Thanks Major, cannt wait to see you post those on here.

NWDS

 
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