Heres another one for ya
2 fridges in a commercial kitchen. Each is 1200W. The plan is to have a single circuit feeding 2 FCU outlets.
This is what I got. Its conduit / trunking and there are 3 other circuits in the same run. so Cg is 0.65
so Ib = 2400/230 = 10.5a
In 16a
Iz = 16/0.65 = 24.6a too much for 2.5 singles method B
So a 10.5a load has to be fed in 4mm because there are other circuits in the same conduit/trunking run?
In the real world I doubt anyone would put it in 4mm!
2 fridges in a commercial kitchen. Each is 1200W. The plan is to have a single circuit feeding 2 FCU outlets.
This is what I got. Its conduit / trunking and there are 3 other circuits in the same run. so Cg is 0.65
so Ib = 2400/230 = 10.5a
In 16a
Iz = 16/0.65 = 24.6a too much for 2.5 singles method B
So a 10.5a load has to be fed in 4mm because there are other circuits in the same conduit/trunking run?
In the real world I doubt anyone would put it in 4mm!