sorry all,
Three pvc insulated cables are connected in parallel, and their resistances are 0.012, 0.015 and 0.008,respectivley,with a total current of 500A flowing on a 240V supply,
A, calculate the current in each cable ( V/R = I )
B, calculate the combined voltage drop over the three cables in parallel,
C, calculate the individual voltage drop over each cable in the paralleled circuit.
I have worked out resistance,
1/0.012 = 83.33 so V/R = I ( 240/0.012 = 20,000 )
1/0.015 = 66.66 so V/R = I (240/0.015 = 16,000 )
1/0.008 = 125 so V/R = I ( 240/0.008 = 30,000 )
am i using the correct formula ( NO ) ???????.
regards NWDS headbangheadbangheadbangheadbangheadbangheadbangheadbangheadbangheadbangheadbangheadbang
Three pvc insulated cables are connected in parallel, and their resistances are 0.012, 0.015 and 0.008,respectivley,with a total current of 500A flowing on a 240V supply,
A, calculate the current in each cable ( V/R = I )
B, calculate the combined voltage drop over the three cables in parallel,
C, calculate the individual voltage drop over each cable in the paralleled circuit.
I have worked out resistance,
1/0.012 = 83.33 so V/R = I ( 240/0.012 = 20,000 )
1/0.015 = 66.66 so V/R = I (240/0.015 = 16,000 )
1/0.008 = 125 so V/R = I ( 240/0.008 = 30,000 )
am i using the correct formula ( NO ) ???????.
regards NWDS headbangheadbangheadbangheadbangheadbangheadbangheadbangheadbangheadbangheadbangheadbang