skystorm Member Joined Jun 27, 2009 Messages 53 Reaction score 0 Location Scotland Sep 17, 2011 #1 Hi all a conductor has across-sectional area of 20mm2 a length of 48m and is made of material with a resistivity of 0.02uohmsm, its resistance is i get 48 can anyone remember me how to work it out thanks
Hi all a conductor has across-sectional area of 20mm2 a length of 48m and is made of material with a resistivity of 0.02uohmsm, its resistance is i get 48 can anyone remember me how to work it out thanks
Dan007 Member Joined Aug 7, 2011 Messages 49 Reaction score 0 Sep 18, 2011 #2 If I remember correct I think it's R=pxL/A R=Resistance p=Resistivity L=Length A=CSA But you have to convert all the numbers into the same unit (0.02/1,000,000)x(48x1000)/20=0.048 - This is converting all units into mm 0.000,000,02 x 48,000,000 / 20=0.048 Hope this helps ut the kettle on
If I remember correct I think it's R=pxL/A R=Resistance p=Resistivity L=Length A=CSA But you have to convert all the numbers into the same unit (0.02/1,000,000)x(48x1000)/20=0.048 - This is converting all units into mm 0.000,000,02 x 48,000,000 / 20=0.048 Hope this helps ut the kettle on
bhamoggy Senior Member Joined Mar 23, 2011 Messages 165 Reaction score 3 Sep 18, 2011 #3 R= pl divided by a ( resistance = resistivity x length divided by csa Answer 0.048
skystorm Member Joined Jun 27, 2009 Messages 53 Reaction score 0 Location Scotland Sep 18, 2011 #4 Thank you bhamoddy and DAN077 that was great help