Hello i need some help with the cable calcuations.
The question is as followd
Lighting Circuit (12 lamps)
Domestic House
Type B Circuit Breaker
Clipped Directly to wooden joist
-(above plasterboard ceiling coverd by thermal insulation exceding 100mm thikness)
Flat twin & earth cable
30 meters lenght of circuit
TNC supply
Ib=
In=
It=
Iz=
Vd=
R1&R2=
Zs=
If=
s=
When i try to solve it i get.
Lighting Circuit (12 lamps) = 1200
Domestic House = 230v
Type B Circuit Breaker
Ib=5.2
In=6a (But i dont know witch one. Closest is 6a but in BS7671 there is 4 diferent circit brakers. It cant be the C and D so is it the "Type B Circuit-Braker to BS EN 60898" or is it "Fuses to BS 88-2.2 and BS 88-6"
Clipped Directly to wooden joist
-(above plasterboard ceiling coverd by thermal insulation exceding 100mm thikness)
Flat twin & earth cable
It= In/Cc*Ci*Cg*Ca*Cr (But i dont need to use the Cc or Cr right?) It say nothing about the "Ambient Temperature" do that mean is 1? and same with "Grouping" 1? The "Thermal Insulation" is that 10.5a 1mm cable?(page 282 BS7671)
In/Ci*Cg*Ca
6/1*1*?(10.5? or 1mm) I think its 10.5 but that be to high so 1?
=6?
(im prity sure somthing is wrong here)
Iz=1mm
30 meters lenght of circuit
44*5.2*30/1000
Vd=6.864
TNCS supply
R1&R2= 1.129
36.20*1.04*30/1000
Zs=7.67
If=29.98
(v(if^2*t))/k=s
(v(29.98^2*0.1))/115=0.082
s=0.082
It would help me very much if somone could tell me what im doing wrong. And how i can correct it. Thanks allot in advance.
The question is as followd
Lighting Circuit (12 lamps)
Domestic House
Type B Circuit Breaker
Clipped Directly to wooden joist
-(above plasterboard ceiling coverd by thermal insulation exceding 100mm thikness)
Flat twin & earth cable
30 meters lenght of circuit
TNC supply
Ib=
In=
It=
Iz=
Vd=
R1&R2=
Zs=
If=
s=
When i try to solve it i get.
Lighting Circuit (12 lamps) = 1200
Domestic House = 230v
Type B Circuit Breaker
Ib=5.2
In=6a (But i dont know witch one. Closest is 6a but in BS7671 there is 4 diferent circit brakers. It cant be the C and D so is it the "Type B Circuit-Braker to BS EN 60898" or is it "Fuses to BS 88-2.2 and BS 88-6"
Clipped Directly to wooden joist
-(above plasterboard ceiling coverd by thermal insulation exceding 100mm thikness)
Flat twin & earth cable
It= In/Cc*Ci*Cg*Ca*Cr (But i dont need to use the Cc or Cr right?) It say nothing about the "Ambient Temperature" do that mean is 1? and same with "Grouping" 1? The "Thermal Insulation" is that 10.5a 1mm cable?(page 282 BS7671)
In/Ci*Cg*Ca
6/1*1*?(10.5? or 1mm) I think its 10.5 but that be to high so 1?
=6?
(im prity sure somthing is wrong here)
Iz=1mm
30 meters lenght of circuit
44*5.2*30/1000
Vd=6.864
TNCS supply
R1&R2= 1.129
36.20*1.04*30/1000
Zs=7.67
If=29.98
(v(if^2*t))/k=s
(v(29.98^2*0.1))/115=0.082
s=0.082
It would help me very much if somone could tell me what im doing wrong. And how i can correct it. Thanks allot in advance.
Last edited by a moderator: