Quick easy question

[kiwiNCFC]

i was reading my 2330 lvl 2 book and it says in there:

for lighting outlets we should assume a

current equivalent to a minimum of 100 W per lampholder. This means that

for a domestic lighting circuit rated at 5 A, a maximum of 11 lighting outlets

could be connected to each circuit

How does the author get 11?

Thanks

EDIT: just had a thought, is it like this: 100X11 = 1100 / 230 = 4.7 meaning a 5amp fuse/mcb would do?

 

[a1]

i was reading my 2330 lvl 2 book and it says in there:for lighting outlets we should assume a

current equivalent to a minimum of 100 W per lampholder. This means that

for a domestic lighting circuit rated at 5 A, a maximum of 11 lighting outlets

could be connected to each circuit

How does the author get 11?

Thanks

EDIT: just had a thought, is it like this: 100X11 = 1100 / 230 = 4.7 meaning a 5amp fuse/mcb would do?

Correct. (On a re-wireable=5A. on a BS60898=6A)

 

[NozSpark]

Yes,,

100w per lamp holder, unles it's a fixed load...

ie flourescent, GU10 barlight..... in which case use the actual load!

 

[SPECIAL LOCATION]

i was reading my 2330 lvl 2 book and it says in there:for lighting outlets we should assume a

current equivalent to a minimum of 100 W per lampholder. This means that

for a domestic lighting circuit rated at 5 A, a maximum of 11 lighting outlets

could be connected to each circuit

How does the author get 11?

Thanks

EDIT: just had a thought, is it like this: 100X11 = 1100 / 230 = 4.7 meaning a 5amp fuse/mcb would do?

So quick a quiestion...

You answered it correctly yourself m8!!!

:^OApplaud SmileyApplaud SmileyApplaud Smiley

But spose it is still good to confirm you ARE thinking on the right lines!

Guiness Drink